Timeline for Equality of subsets of abelian groups
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 16, 2022 at 1:34 | vote | accept | user53093 | ||
| S Jan 16, 2022 at 1:30 | vote | accept | user53093 | ||
| Jan 16, 2022 at 1:34 | |||||
| Jan 14, 2022 at 22:11 | answer | added | Geoff Robinson | timeline score: 2 | |
| Jan 14, 2022 at 9:11 | history | became hot network question | |||
| Jan 14, 2022 at 9:03 | comment | added | YCor | Note that the answer doesn't use $|X|=|Y|$ (which is immediate, namely applied to the trivial representation with character 1). And for non-commutative finite groups, the statement should hold, for the same reason, when $X,Y$ are assumed to be conjugacy-invariant. | |
| Jan 14, 2022 at 5:35 | vote | accept | user53093 | ||
| S Jan 16, 2022 at 1:30 | |||||
| Jan 14, 2022 at 2:06 | answer | added | Absol | timeline score: 6 | |
| Jan 14, 2022 at 1:07 | comment | added | LSpice | Yes, for the same reason as your previous question. | |
| Jan 14, 2022 at 1:06 | history | edited | LSpice | CC BY-SA 4.0 |
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| Jan 14, 2022 at 1:03 | history | asked | user53093 | CC BY-SA 4.0 |