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Jan 13, 2022 at 23:00 history became hot network question
Jan 13, 2022 at 17:34 vote accept user155294
Jan 13, 2022 at 17:14 answer added GH from MO timeline score: 13
Jan 13, 2022 at 16:36 comment added Lucia No. By Stirling's formula and the functional equation $|\zeta(\sigma+it)|$ is about size $|t|^{1/2 -\sigma} |\zeta(1-\sigma+it)|$. So what you write is of size $T{1/2-\sigma} \times T$.
Jan 13, 2022 at 15:26 history edited GH from MO CC BY-SA 4.0
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Jan 13, 2022 at 14:59 history asked user155294 CC BY-SA 4.0