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Jan 14, 2022 at 18:25 comment added Ilya Bogdanov in fact, Claim 2 follows from Claim 1 applied to any prime divisor of ,$2^{n-1}-1$.
Jan 14, 2022 at 17:33 comment added JetfiRex Thanks! And I am also doing other smaller pairs now. I am going to keep updating the question!
Jan 13, 2022 at 9:30 history edited Ilya Bogdanov CC BY-SA 4.0
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Jan 13, 2022 at 9:21 history answered Ilya Bogdanov CC BY-SA 4.0