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Dec 13, 2010 at 19:16 vote accept Vivek Shende
Oct 7, 2010 at 11:30 comment added Dmitri Panov Damiano, huge thanks!! This settles the question
Oct 7, 2010 at 11:24 history edited Dmitri Panov CC BY-SA 2.5
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Oct 7, 2010 at 7:38 comment added damiano On an Enriques surface, a nef divisor class $N$ is either effective or it is the canonical divisor $K$. Indeed, by Riemann-Roch, $\chi(N)=N^2/2+1>0$, and hence either $N$ or $K-N$ is effective. On the other hand, $N$ is nef and hence pseudo-effective, while $K$ is torsion and hence numerically trivial, so that $K-N$ is the opposite of a pseudo-effective class and it can be effective only if it is numerically trivial. Thus $K-N$ is effective only if it is zero, i.e. only if $N=K$.
Oct 6, 2010 at 22:33 history edited Dmitri Panov CC BY-SA 2.5
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Oct 6, 2010 at 22:19 history answered Dmitri Panov CC BY-SA 2.5