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Jan 8, 2022 at 21:26 comment added GH from MO @JunYang No. Even when $\Gamma$ is a co-compact subgroup of $G=\mathrm{SL}_2(\mathbb{R})$, the Laplace eigenvalues occurring in $L^2_{\text{cusp}}(\Gamma\backslash G)$ are elusive (e.g. difficult to compute). In fact the "transcendental nature" of the Laplace eigenvalues (and of Hecke eigenvalues) is one of the attractive features in the subject (at least to me). We cannot put our hands on these eigenvalues directly, hence they are more mysterious, more interesting.
Jan 8, 2022 at 21:03 comment added Jun Yang Thank you! Are the $m_{\pi}$'s known when $\Gamma\backslash G$ is compact?
Jan 8, 2022 at 21:02 vote accept Jun Yang
Jan 8, 2022 at 10:41 history edited GH from MO CC BY-SA 4.0
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Jan 8, 2022 at 10:18 history edited GH from MO CC BY-SA 4.0
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Jan 8, 2022 at 10:07 history answered GH from MO CC BY-SA 4.0