Timeline for The exact domain on which the Euclidean Dirac operator is self-adjoint
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Jan 2, 2022 at 18:08 | comment | added | Branimir Ćaćić | In general, though, if you’re happy working with rapidly decaying smooth functions on $\mathbb{R}^n$ (beyond just compactly supported smooth functions), you can very profitably analyse the Dirac operator on Euclidean $\mathbb{R}^n$ and its functional calculus using the Fourier transform. | |
| Jan 2, 2022 at 17:55 | comment | added | Branimir Ćaćić | This will be the case, at least in the case of Euclidean $\mathbb{R}^n$—see, e.g., this Math.SE thread. | |
| Jan 2, 2022 at 17:31 | vote | accept | Isaac | ||
| Jan 2, 2022 at 17:28 | comment | added | Isaac | Thank you. Then, does the closure of $D^2$ have the domain as $H^2$ then? | |
| Jan 2, 2022 at 15:51 | history | edited | Branimir Ćaćić | CC BY-SA 4.0 |
typos corrected
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| Jan 2, 2022 at 14:48 | history | answered | Branimir Ćaćić | CC BY-SA 4.0 |