Timeline for A variation on Abhyankar–Moh–Suzuki theorem
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 29, 2021 at 13:59 | comment | added | user237522 | Oh, I see, thank you. | |
| Dec 29, 2021 at 13:20 | comment | added | pinaki | Since $\mathbb{C}(f, g) = \mathbb{C}(f, f+g)$, you can simply substitute $g$ by $f+g$. | |
| Dec 29, 2021 at 11:02 | comment | added | user237522 | Thank you for your ideas. My condition (2) says that $\deg(f)=\deg(g)$, so the additional condition that $\deg(f)$ and $\deg(g)$ are relatively prime would imply that $\deg(f)=\deg(g)=1$. | |
| Dec 29, 2021 at 6:24 | history | answered | pinaki | CC BY-SA 4.0 |