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Jan 9, 2022 at 20:24 comment added Andreas Haupt Thanks, dvitek, dynamic programming was a good call. The only think I don't see is how to make it quadratic (and not cubic): I thought that one needs to go trough the matched index of k = n downto 1 and the one for k+1 (which would be stored). That would give cubic time.
Dec 28, 2021 at 2:32 history edited Andreas Haupt CC BY-SA 4.0
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Dec 27, 2021 at 20:55 history edited YCor CC BY-SA 4.0
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Dec 27, 2021 at 16:05 comment added LSpice What does "two sequences $[n]$, $[m]$" mean? As written, your definition seems very specific to (I assume you mean, or maybe you prefer to shift by $1$) $[n] = \{0, \dotsc, n - 1\}$ and $m = \{0, \dotsc, m - 1\}$; do you really mean it to apply to arbitrary sequences?
Dec 27, 2021 at 16:03 comment added dvitek As you've written it this is not a metric, because the minimum always occurs when $E$ is empty. Assuming the definition you probably meant to write (namely, adding the condition that the projections of $E$ onto $[n]$ and $[m]$ are surjective) it is straightforward to write down a dynamic-programming approach to compute $\tilde{d}$ that is quadratic in $\max(m,n)$. So the only interesting question in this post is for what metrics you can approximate this in sub-quadratic time; this may be more suitable for cstheory.SE.
Dec 27, 2021 at 15:38 history asked Andreas Haupt CC BY-SA 4.0