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Dec 27, 2021 at 16:10 comment added mathworker21 $\sum \frac{1}{p\log\log p}$.
Dec 27, 2021 at 15:10 comment added tzimie Thank you, I was also thinking about almost the same. Taking n=100 we get some limit B(100). As n increases, B(n) increases as well. Full set of primes is a limit B(inf). however, it would be much more interesting to have a function F with a property that F(n<666) (or some other value) is finite, while F(667) is not. N(n) is always finite for finite n, so we cant "tackle" the border.
Dec 27, 2021 at 14:56 comment added Gerry Myerson How about the set of all primes $p$ such that there is at least one prime other than $p$ between $p-100$ and $p+100$? I'm guessing the convergence argument for twin primes could be strengthened to apply to such primes, giving a finite-but-large sum.
Dec 27, 2021 at 14:50 comment added Gerry Myerson Reads like a fishing expedition.
Dec 27, 2021 at 14:03 history asked tzimie CC BY-SA 4.0