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Dec 25, 2021 at 21:27 comment added mathoverflowUser @BenjaminSteinberg: thanks for the clarification
Dec 25, 2021 at 20:48 comment added Benjamin Steinberg Now that you replaced deg^2 by deg this is just the standard statement that an irreducible representation appears with multiplicity equal to its degree in the regular representation and so your sum is computing the character of the regular representation which is 0 on all nonidentity elements and |G| on the identity
Dec 25, 2021 at 19:52 vote accept mathoverflowUser
Dec 25, 2021 at 19:52 comment added mathoverflowUser I am not sure I understand your answer. Can you please relate to the notation used in the question?
Dec 25, 2021 at 15:37 comment added Benjamin Steinberg Since @GeoffRobinson's comment is no longer here it said the desired result is false for the symmetric group on 3 letters where g has order 3.
Dec 25, 2021 at 14:45 comment added Yemon Choi In light of the error, I don't really think this counts as a "solution". This is a bit like saying "the value of six times nine is 42 (if you replace the nine by seven)"
Dec 25, 2021 at 14:03 comment added user130903 I realised that and already edited my solution accordingly.
Dec 25, 2021 at 14:02 comment added Benjamin Steinberg The regular character is the sum of $deg(\rho)\chi_{\rho}$ without the square. So what you want is true without the square but false with the square as @GeoffRobinson explained
Dec 25, 2021 at 13:59 history edited user130903 CC BY-SA 4.0
added 72 characters in body
Dec 25, 2021 at 13:38 comment added Tommaso Scognamiglio I'm sorry but what do you mean by Plancherel theorem?
Dec 25, 2021 at 12:37 vote accept mathoverflowUser
Dec 25, 2021 at 13:50
Dec 25, 2021 at 12:37 comment added mathoverflowUser thanks for your insight
Dec 25, 2021 at 12:34 history answered user130903 CC BY-SA 4.0