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Dec 28, 2021 at 21:44 answer added Dirk timeline score: 4
Dec 28, 2021 at 21:22 answer added Shannon Starr timeline score: 3
Dec 28, 2021 at 20:44 answer added Daniele Tampieri timeline score: 2
Dec 24, 2021 at 10:52 comment added Dave L Renfro R.e. my last comment, this analogy may help. It can be useful to know the values of a (real-valued) function are bounded, and in many such cases (e.g. establishing error bounds for expressions containing the function) assuming the function is nice in some way so as to imply this (such as continuity on a compact set, or more generally the function has a uniformly bounded limit at each point such as this function) is an additional condition that is both unnecessary and somewhat obscures what really matters (boundedness of function values).
Dec 24, 2021 at 3:42 vote accept 12345
Dec 24, 2021 at 0:41 answer added WeakLearner timeline score: 7
Dec 23, 2021 at 19:28 comment added Dave L Renfro It's probably worth observing that Lipschitz continuity is equivalent to having bounded rates of change, without the presumably (for these applications) unnecessary additional condition that all the pointwise limits of these rates of change actually exist.
Dec 23, 2021 at 16:42 comment added Pietro Majer In general, talking of non-linear functional analysis in Banach spaces, just note that a Banach space may fail to have non-zero $C^1$ functions with bounded support. This means, no $C^1$ partitions of unity. On the other hand, locally Lipschits partitions of unity are available for free by means of the norm. So it is a lucky coincidence that the best regularity always available to build maps and vector fields is also the minimum requirement for well posedness of ODE.
Dec 23, 2021 at 16:00 answer added Iosif Pinelis timeline score: 3
Dec 23, 2021 at 14:17 history edited 12345 CC BY-SA 4.0
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Jan 7, 2022 at 3:04
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Dec 23, 2021 at 14:00
S Dec 23, 2021 at 13:58 history asked 12345 CC BY-SA 4.0