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Timeline for Is $C_n$ infinitely log-convex?

Current License: CC BY-SA 4.0

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Dec 23, 2021 at 19:44 vote accept T. Amdeberhan
Dec 23, 2021 at 14:32 comment added Iosif Pinelis Indeed, they must be, because of the Weierstrass approximation theorem. :-)
Dec 23, 2021 at 12:24 comment added Fedor Petrov @IosifPinelis I guess they are distributionally the same:)
Dec 22, 2021 at 21:37 comment added Iosif Pinelis This is very nice. Other integral representations of $(C_n)$ as mixtures of geometric progressions are also known; see e.g. en.wikipedia.org/wiki/Catalan_number#Properties
Dec 22, 2021 at 20:18 history answered Fedor Petrov CC BY-SA 4.0