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Dec 23, 2021 at 11:52 comment added user1005113 Thanks, Jeremy!
Dec 23, 2021 at 10:24 comment added Jeremy Rickard @user1005113 I'm no expert, and won't embarrass myself by trying to give a formal definition, but my informal (and possibly wrong) understanding is that it refers to a way of making a model of $\tau$ from a model of $\sigma$ by defining the $\tau$-operations in terms of the $\sigma$-operations. For example, there is a homomorphism from the theory of Lie algebras to the theory of associative algebras since we can regard an associative algebra as a Lie algebra by defining $[x,y]:=xy-yx$.
Dec 22, 2021 at 23:25 comment added user1005113 @JeremyRickard In your link, what is a homomorphism $\tau \to \sigma$ of finitary algebraic theories? (It is remarked that "if $τ→σ$ is a homomorphism and $σ$ satisfies IBN, then also $τ$ satisfies IBN".)
Dec 22, 2021 at 19:34 comment added Maxime Ramzi I asked the same question here : math.stackexchange.com/questions/3325594/… - Eric Wofsey answered with the universal counterexample
Dec 22, 2021 at 15:49 comment added user1005113 That's very helpful, thanks!
Dec 22, 2021 at 15:43 comment added Keith Kearnes If the operations of the variety are finitary and the variety does not satisfy $x\approx y$, then it is the case that $F_V(X)\cong F_V(Y)$ implies $X\cong Y$ whenever $X$ is infinite. This is Theorem 1 of ``Note on the Isomorphism Problem for Free Algebraic Systems'' by Tsuyoshi Fujiwara, 1955.
Dec 22, 2021 at 15:23 history closed მამუკა ჯიბლაძე
Benjamin Steinberg
CommunityBot
Duplicate of IBN for algebraic theories
Dec 22, 2021 at 15:21 comment added Benjamin Steinberg If a variety of universal algebras has a non trivial finite object then you do get injectvity. I don't know if this counts as usually
Dec 22, 2021 at 15:11 comment added Benjamin Steinberg For Jonsson-Tarski algebras the free objects on any two finite sets are isomorphic
Dec 22, 2021 at 14:54 vote accept user1005113
Dec 22, 2021 at 14:35 answer added Jeremy Rickard timeline score: 8
Dec 22, 2021 at 14:31 comment added Jeremy Rickard Related question: mathoverflow.net/questions/126747/ibn-for-algebraic-theories
Dec 22, 2021 at 14:23 answer added Tom Leinster timeline score: 6
Dec 22, 2021 at 14:19 comment added Mike Shulman Correct me if I'm wrong, but isn't the terminal category a variety of algebras, for the theory with one nullary operation $p$ and one equation $\forall x (p=x)$? Its free functor is certainly not injective up to isomorphism.
Dec 22, 2021 at 13:48 comment added Yemon Choi The abelianization functor from Grp to Ab is left adjoint to the forgetful functor, but is not injective on objects up to isomorphism.
Dec 22, 2021 at 13:39 history asked user1005113 CC BY-SA 4.0