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Jan 4, 2022 at 0:51 history undeleted Gabe Goldberg
Jan 4, 2022 at 0:48 history edited Gabe Goldberg CC BY-SA 4.0
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Dec 20, 2021 at 14:22 history deleted Gabe Goldberg via Vote
Dec 20, 2021 at 14:22 comment added Gabe Goldberg I think defining a surjection from $\omega^\omega$ onto the result of applying the Suslin operation to all countable sequences of open sets is all a bit more subtle than I thought, so I'm going to delete this answer... One shouldn't try to work in ZF at 5am I guess.
Dec 20, 2021 at 14:07 comment added Gabe Goldberg Also I think Kechris's book Classical Descriptive Set Theory says a lot about analytic and coanalytic sets as does Moschovakis's Descriptive Set Theory.
Dec 20, 2021 at 13:56 comment added Gabe Goldberg I made some edits, hope that clears things up
Dec 20, 2021 at 13:54 history edited Gabe Goldberg CC BY-SA 4.0
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Dec 20, 2021 at 13:49 comment added Clement Yung Sorry, I'm not sure what you're saying. Can you elaborate?
Dec 20, 2021 at 13:46 comment added Gabe Goldberg I guess was considering all sets obtained applying your Suslin operation to schemes of open sets, which may not itself be closed under your Suslin operation in ZF.
Dec 20, 2021 at 13:44 comment added Clement Yung Also, do you suggest any references that I can refer to for an exploration on the theory of coanalytic sets?
Dec 20, 2021 at 13:43 comment added Clement Yung Thank you very much! However, it appears that as Gerald Edgar suggested, in a model of $\mathsf{ZF}$ which every subset of reals is a countable union of countable sets, so trivially every subset of reals is Suslin measurable (and hence there doesn't exist a Baire set that is not Suslin measurable). Why does that not contradict your proof?
Dec 20, 2021 at 13:33 history answered Gabe Goldberg CC BY-SA 4.0