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Jan 6, 2022 at 12:29 history edited Clement Yung CC BY-SA 4.0
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Jan 6, 2022 at 12:28 comment added Clement Yung @AsafKaragila I agree. I'll take note in the future.
Jan 6, 2022 at 12:27 comment added Asaf Karagila Okay. Just a general writing tip, when a definition is short, or is often known by several different names, one should not refer the reader elsewhere, but instead just include the definition or a clarification.
Jan 6, 2022 at 12:25 comment added Clement Yung @AsafKaragila I'm just following the terminology in Todorcevic's book.
Jan 6, 2022 at 12:25 history edited Clement Yung CC BY-SA 4.0
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Jan 6, 2022 at 12:24 comment added Asaf Karagila Wouldn't it be easier to just say "the Boolean algebra generated by the open sets"? (Or at least "the algebra of sets"?)
Jan 6, 2022 at 12:23 comment added Clement Yung @AsafKaragila please see my edit.
Jan 6, 2022 at 12:23 history edited Clement Yung CC BY-SA 4.0
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Jan 6, 2022 at 12:18 comment added Asaf Karagila What is "the field of open subsets"?
Jan 6, 2022 at 7:23 history edited Clement Yung CC BY-SA 4.0
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Dec 22, 2021 at 5:02 vote accept Clement Yung
Dec 20, 2021 at 18:57 answer added Gerald Edgar timeline score: 7
Dec 20, 2021 at 16:19 comment added Emil Jeřábek @DaveLRenfro The OP's Suslin measurable sets are coanalytic rather than analytic.
Dec 20, 2021 at 16:15 comment added Dave L Renfro as well as ZFC-consistently beyond Baire and Lebesgue measurable sets (beginning with 2nd level?), but they are also less "explicitly definable". I don't know all that much about this, but I believe one way of viewing things is that the better known projective set operation can, in some sense (in a way independent of ZFC?), leap-frog over a lot of this other stuff rather quickly.
Dec 20, 2021 at 16:06 comment added Dave L Renfro Unless I'm missing something, your Suslin (measurable) sets are the same as what I (and the references I cited) call Suslin sets, which are also called analytic sets (an unfortunate term that could suggest a close connection with complex-analytic functions or with analytic sets in algebraic geometry, although the term analytic set as used here has been around since the 1920s I think). Incidentally, the hierarchy of projective sets goes well beyond the $R$-sets (continued)
Dec 20, 2021 at 15:45 comment added Clement Yung @DaveLRenfro just to check, your Suslin set is the complement of a Suslin measurable set? (complement of analytic is coanalytic)
Dec 20, 2021 at 15:21 comment added Dave L Renfro in which the applications of these two processes are interlaced, with a reasonable limiting/union of previous hierarchy levels at limit ordinal levels), and the much more exotic higher levels of Kolmogorov's $R$-sets (see here also). Finally, The Ramsey sets and related sigma algebras and ideals by Jack Brown (1990) might be useful.
Dec 20, 2021 at 15:21 comment added Dave L Renfro In ordinary ZFC, there is a huge gap between Suslin sets (= analytic sets) and Baire sets that is very analogous to the huge gap between Suslin sets and Lebesgue measurable sets. Indeed, there is even a huge gap between Suslin sets and sets simultaneously Baire and Lebesgue measurable. Regarding this last gap, one finds in it the $\sigma(\Sigma_1^1)$ sets $(\sigma$-algebra generated by the Suslin sets), and the $C$-sets (the collection of sets closed under $\sigma$-algebra generation and the Suslin operation -- the end result of an $\omega_1$-length hierarchy (continued)
Dec 20, 2021 at 14:56 history edited Clement Yung CC BY-SA 4.0
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Dec 20, 2021 at 13:40 history edited Clement Yung CC BY-SA 4.0
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Dec 20, 2021 at 13:33 answer added Gabe Goldberg timeline score: 2
Dec 20, 2021 at 13:32 comment added Andreas Lietz It seems to me that this definition of Suslin measurability yields exactly the coanalytic sets (cf. Moschovakis Theorem 2B.1 & 2B.2, note that there the Suslin operation is the "complement" of the Suslin operation here). So the universal analytic set should do the trick. This all works in ZF+DC.
Dec 20, 2021 at 13:32 history edited Clement Yung CC BY-SA 4.0
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Dec 20, 2021 at 13:30 comment added Clement Yung @GeraldEdgar also yes, indeed the Feferman-Levy model works for my second question. Thank you.
Dec 20, 2021 at 13:30 comment added Clement Yung @GeraldEdgar The only proof of Nikodym's result I can find is in Todorcevic's book, in which a lemma requires the Banach Category theorem. According to the comments in this answer, the full AC is required. I can't find the original paper for his result.
Dec 20, 2021 at 13:09 history edited Clement Yung CC BY-SA 4.0
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Dec 20, 2021 at 12:52 comment added Gerald Edgar Define "Baire subsets", there are two different things possible with this name. Does ZF prove Nikodym's result? Surely a countable union of countable sets is Suslin measurable? And ZF cannot disprove: "every subset of $\mathbb R$ is a countable union of countable sets".
Dec 20, 2021 at 12:16 history asked Clement Yung CC BY-SA 4.0