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Oct 11, 2010 at 17:13 vote accept Jill
Oct 5, 2010 at 16:22 history edited Cam McLeman CC BY-SA 2.5
added 65 characters in body
Oct 5, 2010 at 16:15 history edited Cam McLeman CC BY-SA 2.5
added 181 characters in body; added 257 characters in body
Oct 5, 2010 at 4:16 comment added Cam McLeman Of course, $N(a-b)\neq N(a)-N(b)$, so this is a looser notion of "congruence of something in the integers" than in Gerry's answer.
Oct 5, 2010 at 4:14 history answered Cam McLeman CC BY-SA 2.5