Timeline for Congruences mod primes in Galois extensions
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 5, 2010 at 6:05 | comment | added | Gerry Myerson | Oops, I meant $3+\zeta_3$ and $3+\zeta_3^2$, whose product is 7. | |
| Oct 5, 2010 at 4:34 | comment | added | Cam McLeman | (but good answer). | |
| Oct 5, 2010 at 4:19 | comment | added | Cam McLeman | I don't think your factorization of 7 is correct. In particular, $N(3-\zeta)=(3-\zeta)(3-\zeta^2)=9+3+1=13$. | |
| Oct 5, 2010 at 4:03 | history | answered | Gerry Myerson | CC BY-SA 2.5 |