Timeline for An inequality about quasi-linear function
Current License: CC BY-SA 4.0
8 events
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Dec 17, 2021 at 11:51 | history | edited | Mr.xue | CC BY-SA 4.0 |
update
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Dec 12, 2021 at 1:53 | history | edited | Mr.xue | CC BY-SA 4.0 |
Add some content
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Dec 12, 2021 at 1:22 | comment | added | Mr.xue | @username I think that I first need to prove the inequality, then using standard Osgood lemma to prove Lemma 1.2. Is it right? | |
Dec 11, 2021 at 19:13 | comment | added | username | You did not read Lemma 1.2 correctly. Read it again (suppose further..). | |
Dec 10, 2021 at 10:46 | comment | added | Mr.xue | @username Thanks for your reply. I think your idea is helpful to solve this question. However, I also don't know how to complete the rest part of the proof. | |
Dec 10, 2021 at 9:54 | comment | added | username | Here is a.n idea. Suppose $n=2^k\Leftrightarrow k = \ln n/\ln2$. Then $$ \gamma(n)\leq 2C\gamma(2^{k-1})\leq \cdots \leq 2^k C^k = n C^{\ln n/\ln2} =n^{1+\ln C/\ln2}. $$ It doesn't show $t^2$, but it shows no larger than $t^{1+\frac{\ln C}{\ln 2}}$. Is that enough? | |
Dec 10, 2021 at 8:19 | history | edited | YCor | CC BY-SA 4.0 |
changed tag, formatting
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Dec 10, 2021 at 8:10 | history | asked | Mr.xue | CC BY-SA 4.0 |