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Oct 5, 2010 at 7:49 comment added Herman Tulleken Ok, a few quick tests in Matlab shows that even in the range $[0 \pi/2]$ that the indefinite sum of Taylor series does not converge. In light of what Oleg Eroshkin said below, this makes sense, so this method cannot be used for finding an approximation.
Oct 4, 2010 at 16:05 comment added Herman Tulleken The indefinite integral (typically) requires the use of substitution, which exists because of the "nice" chain rule for differentiation. Differencing does not have a nice chain rule (there are some variants, but they do not help in this case). I'll play with truncated Taylor series and see where it gets me (I guess I should have tried that already).
Oct 4, 2010 at 16:03 history edited decomwe CC BY-SA 2.5
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Oct 4, 2010 at 15:58 history answered decomwe CC BY-SA 2.5