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Dec 10, 2021 at 14:51 vote accept wonderich
Dec 8, 2021 at 16:33 comment added Tyler Lawson @DenisNardin good point, thank you!
Dec 8, 2021 at 16:33 history edited Tyler Lawson CC BY-SA 4.0
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Dec 8, 2021 at 0:16 comment added wonderich yes, thanks Tyler for the nice answer. I agree with Denis Nardin, too!
Dec 7, 2021 at 20:59 comment added Denis Nardin Just to avoid a possible ambiguity of notation, I want to write that with $\mathbb{Z}^r\oplus \mathbb{Z}/2^s$ you mean $\mathbb{Z}^r\oplus (\mathbb{Z}/2)^s$ (so the second factor is not a cyclic group)
Dec 7, 2021 at 16:23 history edited Tyler Lawson CC BY-SA 4.0
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Dec 7, 2021 at 16:17 history answered Tyler Lawson CC BY-SA 4.0