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Dec 7, 2021 at 9:47 comment added Ilya Bogdanov @Fedor Yes I know, I merely wanted to share a bit prettier construction;)
Dec 7, 2021 at 8:58 vote accept Dominic van der Zypen
Dec 7, 2021 at 7:43 comment added Fedor Petrov If infinite edges are allowed, we could simply take the disjoint edges $A_{n1}, A_{n2}, \dots, A_{nn} $ for all $n=1,2, \dots$, and add vertices so that $A_{ni}$ and $A_{kj}$ for $n\ne k$ are not disjoint anymore.
Dec 7, 2021 at 7:35 history answered Ilya Bogdanov CC BY-SA 4.0