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S Apr 28, 2022 at 17:10 vote accept Saúl RM
Dec 9, 2021 at 4:20 answer added Aitor Iribar Lopez timeline score: 3
Dec 5, 2021 at 18:09 history became hot network question
Dec 5, 2021 at 16:08 vote accept Saúl RM
S Apr 28, 2022 at 17:10
Dec 5, 2021 at 15:39 answer added Pierre PC timeline score: 4
Dec 5, 2021 at 12:05 comment added Jochen Wengenroth I doubt that this is true. There are simple examples which fail to be manifolds, e.g., $X= [0,1]\times \{0\} \cup \{0\}\times [0,\infty) \cup \bigcup_{n\in\mathbb N} \{1/n\}\times [0,n]$ and $K=[0,1]\times [0,1]$. Perhaps one can make such a comb a manifold in higher dimensions.
Dec 5, 2021 at 10:09 history asked Saúl RM CC BY-SA 4.0