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S Dec 21, 2021 at 14:06 history bounty ended CommunityBot
S Dec 21, 2021 at 14:06 history notice removed CommunityBot
S Dec 13, 2021 at 12:34 history bounty started H A Helfgott
S Dec 13, 2021 at 12:34 history notice added H A Helfgott Draw attention
Dec 6, 2021 at 7:50 comment added H A Helfgott And yes, by the linear independence of $\pi$ and $\log 2, \log 3,\dotsc,\log p$ over $\mathbb{Q}$, $t$ and $\chi$ can conspire, and so the bound is tight, for $t$ and $\chi$ unbounded. (As @juan points out below - use Kronecker's theorem.)
Dec 6, 2021 at 7:48 history edited H A Helfgott CC BY-SA 4.0
edited body
Dec 6, 2021 at 7:48 comment added H A Helfgott Important self-correction: I should have said $\arcsin$, not $\arctan$. You still get a tighter upper bound.
Dec 4, 2021 at 19:51 history edited GH from MO CC BY-SA 4.0
edited body
Dec 4, 2021 at 17:44 answer added juan timeline score: 3
Dec 4, 2021 at 17:09 history edited YCor CC BY-SA 4.0
fixed typo
Dec 4, 2021 at 16:41 history asked H A Helfgott CC BY-SA 4.0