Skip to main content
4 events
when toggle format what by license comment
Dec 1, 2021 at 10:56 comment added Sijie Luo Ha, I think I have found out a counterexample. Let $A=\begin{pmatrix}1&0\\0&-1\end{pmatrix}$, $B=\begin{pmatrix}2&0\\0&0\end{pmatrix}$ and $U=\begin{pmatrix}0&1\\1&0\end{pmatrix}$. It is easy to verify that $\sum_{j=1}^{n}|\lambda_{j}(A+B)|\not=\sum_{j=1}^{n}|\lambda_{j}(U^{*}AU+B)|$. Thank you for your enlightening example! @Chris Ramsey
Dec 1, 2021 at 9:12 comment added Sijie Luo Many thanks for your wonderful example! And I have a further question: Dose $\sum_{j=1}^{n}|\lambda_{j}(UAU^{*}+B)|=\sum_{j=1}^{n}|\lambda_{j}(A+B)|$ hold true? The example you cnstructed above do satisfy this relation. Here $(\lambda_{j}(C))_{j=1}^{n}$ are eigenvalues of a $n\times n$ hermitian matrix $C$.
Dec 1, 2021 at 9:02 vote accept Sijie Luo
Nov 30, 2021 at 16:34 history answered Chris Ramsey CC BY-SA 4.0