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Nov 29, 2021 at 16:20 comment added Guillaume Aubrun It may not be related to your maximization problem, but let me point that the Banach-Mazur distance between the regular hexagon and the square is 3/2, which is the maximal value for a pair of centrally symmetric convex bodies.
Nov 29, 2021 at 15:32 comment added Gericault Indeed thats a counterexample. The smallest rectangle enclosing the regular hexagon is $[-\sqrt{3}/2 ; \sqrt{3}/2] \times [-1;1]$ the area ratio is then $4/3$, while for the ball it is $4/\pi$.
Nov 29, 2021 at 15:07 history edited Gericault CC BY-SA 4.0
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Nov 29, 2021 at 15:05 comment added Guillaume Aubrun Does this work for the regular hexagon?
Nov 29, 2021 at 14:09 history asked Gericault CC BY-SA 4.0