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Nov 28, 2021 at 1:43 comment added Elliot Glazer $\kappa$ has the property $`` \exists \alpha < \kappa$ such that $V_{\alpha} \equiv_{\text{SOL}} V_{\kappa}"$ because $M$ thinks $j(\kappa)$ has that property.
Nov 28, 2021 at 0:33 comment added Noah Schweber @ElliotGlazer Isn't that $M$-superscript a problem though?
Nov 28, 2021 at 0:32 comment added Elliot Glazer Yes measurables work, because for $j: V \rightarrow M$ with critical point $\kappa,$ $V_{\kappa+1}^M$ and $V_{j(\kappa)+1}^M$ have the same theory.
Nov 27, 2021 at 23:11 comment added Noah Schweber @AsafKaragila Yes, basically $\Sigma^1_\omega$-indescribability (for theories instead of individual sentences, but I don't think that changes the strength too much). I guess measurables, being $\Pi^2_1$-indescribable, would probably do the trick.
Nov 27, 2021 at 22:42 comment added Asaf Karagila Wouldn't that be something similar to indescribable cardinals?
Nov 27, 2021 at 22:22 history edited Noah Schweber CC BY-SA 4.0
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Nov 27, 2021 at 22:14 history answered Noah Schweber CC BY-SA 4.0