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Timeline for Is there a noncommutative Gaussian?

Current License: CC BY-SA 4.0

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May 10, 2022 at 21:20 history edited LSpice CC BY-SA 4.0
Titles of references, while this is on the front page
Feb 25, 2022 at 3:07 comment added Terry Tao Fair point. I have narrowed the claim about entropy to the classical and free cases.
Feb 25, 2022 at 3:06 history edited Terry Tao CC BY-SA 4.0
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Feb 25, 2022 at 0:07 comment added Octavio Arizmendi Is there really a notion of monotone entropy? To the best of my knowledge this is not defined anywhere.
Nov 28, 2021 at 19:19 history edited Terry Tao CC BY-SA 4.0
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Nov 28, 2021 at 19:13 history edited Terry Tao CC BY-SA 4.0
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Nov 28, 2021 at 19:08 comment added Terry Tao @WillSawin In noncommutative settings the $2k^{th}$ moment of a sum of $2k$ independent mean zero variables (for any of the non-commutative notions of independence) contains only exponentially many non-trivial terms, as opposed to factorially many in the classical case. (compare for instance the number of non-crossing perfect matchings in $\{1,\dots,2k\}$ against the number of unrestricted perfect matchings). This already largely explains the boundedness phenomenon.
Nov 28, 2021 at 19:04 history edited Terry Tao CC BY-SA 4.0
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Nov 28, 2021 at 11:21 vote accept Pulcinella
Nov 27, 2021 at 17:17 comment added Will Sawin It's interesting that they're all bounded (although I guess that the Gaussian is, for most practical purposes, bounded.)
Nov 27, 2021 at 16:45 history answered Terry Tao CC BY-SA 4.0