Timeline for Efficient Method for Calculating the Probability of a Set of Outcomes?
Current License: CC BY-SA 2.5
3 events
| when toggle format | what | by | license | comment | |
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| Oct 4, 2010 at 3:20 | comment | added | Ross Millikan | Each row represents a number of games won, lost and tied. So I confused you because it should be 3^11=177477 rows instead of 11^3=1331. And Excel won't do that many. At the start, the probability of (0-0-0) is 1. Let pn(win) be the probability of winning game n. pn(loss) is the probability of losing game n. Then the probability of (1-0-0) is p(0-0-0)*p1(win). The probability of (1-1-0) is p(1-0-0)*p2(loss)+p(0-1-0)*p2(win). The message in problems like this is to lose the info you don't need. After game 5, you don't need to know which games were won,lost,drawn-just how many | |
| Oct 3, 2010 at 4:49 | comment | added | Kenny | Can you explain a little bit more about what would go in rows 7-1338? You can assume there are only 2 games to keep in simple. Therefore the possible outcomes are (W-L-T): (2-0-0), (1-1-0). (1-0-1-). (0-1-1). (0-2-0). (0-0-2) | |
| Oct 3, 2010 at 4:03 | history | answered | Ross Millikan | CC BY-SA 2.5 |