Timeline for Collecting alternative proofs for the oddity of Catalan
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 23, 2021 at 2:24 | history | edited | Noam D. Elkies | CC BY-SA 4.0 |
fix mistake in indexing the sum for $F$, and also correct two minor typos (missing ")", and \cdots for \ldots)
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| Nov 20, 2021 at 22:16 | comment | added | T. Amdeberhan | I like it. Thank you. | |
| Nov 20, 2021 at 22:09 | comment | added | Noam D. Elkies | More or less the same, yes (and it would be closer if I organized the argument so that it never explicitly uses $(a+b)^{2^r} \equiv a^{2^r} + b^{2^r}$ for $r > 1$); but I think that formulating it in terms of generating functions shows more clearly what's going on. | |
| Nov 20, 2021 at 22:04 | comment | added | Sam Hopkins | I think this is basically the same as the proof by Koshy and Salmassi linked to in Carlo Beenakker's answer. | |
| Nov 20, 2021 at 22:02 | history | answered | Noam D. Elkies | CC BY-SA 4.0 |