Skip to main content
7 events
when toggle format what by license comment
Nov 19, 2021 at 19:18 history edited GH from MO CC BY-SA 4.0
deleted 2 characters in body
Nov 19, 2021 at 19:14 comment added GH from MO Nice. Your proof is similar to the argument in my post, but of course subtly different. I should add that for Casorati-Sochotski-Weierstrass you probably need that $f(1/z)$ has an isolated singularity at $z=0$. This is clear of course, since $f$ has at most $d$ poles (applying your argument for $a=0$ and for $1/f$ in place of $f$).
Nov 19, 2021 at 19:14 comment added Wojowu Lovely, thank you for elaborating!
Nov 19, 2021 at 18:39 history edited Alexandre Eremenko CC BY-SA 4.0
added 436 characters in body
Nov 19, 2021 at 18:32 comment added Alexandre Eremenko Sure. With a few extra words you can appeal to Casoratti-Weierstrass theorem.
Nov 19, 2021 at 14:50 comment added Wojowu Is there a way to justify your last "therefore $f$ is rational" without appealing to something like great Picard theorem?
Nov 19, 2021 at 14:17 history answered Alexandre Eremenko CC BY-SA 4.0