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Jul 21, 2022 at 12:49 history edited Martin Sleziak CC BY-SA 4.0
replaced the dead link
Nov 19, 2021 at 17:05 history edited François Brunault CC BY-SA 4.0
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Nov 19, 2021 at 17:03 comment added François Brunault @Henri The terminology "Bernoulli distribution" is ambiguous, indeed it certainly does not suffice to check just one relation. Rather one should consider the Stickelberger distribution associated to $B_1$, which Kubert and Lang also call the Bernoulli distribution. I hope I made it clearer now in the answer.
Nov 19, 2021 at 16:59 history edited François Brunault CC BY-SA 4.0
Expanded and made clearer the part about Bernoulli distributions
Nov 19, 2021 at 15:30 comment added Henri Cohen I am not sure that I understand what you mean by being in the kernel of the Bernoulli distribution: for instance the beta function $B(a,b)=\Gamma(a)\Gamma(b)/\Gamma(a+b)$ is certainly not always a power of $\sqrt{\pi}$ times algebraic, but $B_1(a)+B_1(b)-B_1(a+b)$ is always integral (sorry, forgot the $1/2$ but you can square).
Nov 19, 2021 at 10:37 history answered François Brunault CC BY-SA 4.0