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Feb 6, 2023 at 16:36 comment added Edward Sorry, I was thinking that it is correct only for large $m$ and $n$, but it should be also correct for small values. Just use the SVD of $X$ to show it.
Feb 6, 2023 at 12:14 comment added John Can you provide some examples to show that this conclusion is incorrect? Do you mean $$E[X^{+}X]=\frac{m}{n}I$$ does not hold for $m>n$ or this statement has not been proved yet? We test this statement in matlab, and it seems correct when $m\leq n$.
Feb 6, 2023 at 9:18 comment added Edward It is in fact incorrect for general $m$ and $n$, fixed.
Feb 6, 2023 at 9:16 history edited Edward CC BY-SA 4.0
delete incorrect special case
Feb 5, 2023 at 18:31 comment added John why for the special case it holds that $\bf E[X^+X]=\frac{m}{n}I$, I am very confused, can you give the reference of this property?
Nov 18, 2021 at 17:44 answer added Iosif Pinelis timeline score: 3
Nov 18, 2021 at 14:45 history asked Edward CC BY-SA 4.0