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Nov 18, 2021 at 0:10 vote accept RFZ
Nov 18, 2021 at 0:10 comment added RFZ Great! Thank you so much, Fedor! +1
Nov 17, 2021 at 4:58 comment added Fedor Petrov We construct a function from $A+B+nS$ to subsets of $(A+B)^{n+1}$ such that each subset has size at least $\alpha^n$ and these subsets are disjoint.
Nov 16, 2021 at 23:36 comment added RFZ Dear Fedor! I think that I got your point. But let me ask you a minor a question: I edited my question yesterday when I added an edit but later I deleted but you can see it anyway. So my point was basically to construct some function from $A+B+nS$ to $(n+1)(A+B)$ with desired properties (please see my edit). But in your answer do you construct implicitly some function from $A+B+nS$ to $(A+B)^{n+1}$? I guess no. You claim is that from any element of $A+B+nS$ you can construct $\geq \alpha^n$ elements from $(A+B)^{n+1}$.
Nov 16, 2021 at 8:46 history answered Fedor Petrov CC BY-SA 4.0