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Nov 13, 2021 at 20:00 comment added Chris Ramsey Perhaps one could do something clever with Takai duality: $C^*_r(G) \otimes \mathcal K \simeq (C^*_r(G) \times_\alpha H) \times_{\hat\alpha} \hat H$. By clever, I mean realizing the right-hand-side above as another $C^*_r(G_2)$ where $G$ and $G_2$ are non-isomorphic.
Nov 12, 2021 at 22:09 comment added Yemon Choi If we assume Kadison-Kaplansky, is it known that $M_2(C_r^*(G_1))\cong M_2(C_r^*(G_2))$ implies $C_r^*(G_1)\cong C_r^*(G_2)$? (I was thinking very half-heartedly about pushing matrix units from one algebra over to the other and then trying to play games with traces, but I don't pretend to have thought this through.)
Nov 12, 2021 at 19:06 history edited YCor CC BY-SA 4.0
fixed typo
Nov 12, 2021 at 18:36 history asked Caleb Eckhardt CC BY-SA 4.0