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Nov 10, 2021 at 21:33 comment added YCor Side remark: Even without connectedness assumption: every locally compact topological field that is algebraically closed is isomorphic to $\mathbf{C}$ as topological field.
Nov 10, 2021 at 20:19 comment added marco2013 This answers the question. Sorry, I was not clear. By "isomorphic", I mean algebraically and topologically isomorphic.
Nov 10, 2021 at 20:00 comment added Laurent Moret-Bailly Apparently Dieudonné has constructed proper dense subfields of $\mathbb{C}$ which are connected and algebraically isomorphic to $\mathbb{C}$. I don't know if this answers the question since the meaning of "isomorphic" is unclear. See chapter X of Wieslaw's book. In the same chapter there is this result of Bergman and Waterman (Theorem 7): "Every discrete field can be embedded in an arcwise connected topological field". But of course algebraic closedness is not mentioned.
Nov 10, 2021 at 19:39 history edited marco2013
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S Nov 10, 2021 at 19:22 review First questions
Nov 10, 2021 at 19:44
S Nov 10, 2021 at 19:22 history asked marco2013 CC BY-SA 4.0