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Nov 6, 2021 at 15:15 comment added user164898 Better put a bound on the number of cells in $X$, or demand that the homotopy groups of $X$ are finitely generated, or something else along those lines. Otherwise you have a proper class of such spaces $X$ (this already happens when $n=2$ and $G$ is trivial), so no hope of such a moduli space.
Nov 6, 2021 at 14:29 comment added Connor Malin Such a moduli space, if reasonably defined, would be a union of $B(\operatorname{haut}(X))$ over all $X$ with $\pi_1(X)=G$. Here $B$ denotes the classifying space of a monoid and $\operatorname{haut}$ denotes homotopy automorphisms. Spaces like this are useful, but not to study $\pi_1$.
Nov 6, 2021 at 14:26 history edited LSpice CC BY-SA 4.0
Link to @YCor's comment
Nov 6, 2021 at 13:36 history edited Abh CC BY-SA 4.0
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Nov 6, 2021 at 13:33 comment added YCor You'll have no control, even on the homotopy type, if you don't assume path-connected, and you'll need even more (otherwise one can crook things by adding fake loops that are not paths). So "locally path-connected" would help too. Maybe a starting point if you want a moduli space is to figure out what you need when $G=1$.
Nov 6, 2021 at 13:29 history asked Abh CC BY-SA 4.0