Timeline for Langlands in dimension 2: the Yoshida conjecture
Current License: CC BY-SA 2.5
18 events
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Oct 11, 2010 at 9:07 | comment | added | François Brunault | @Kevin Buzzard: It would be definitely worth trying the strategy you outline in the comments to David Hansen's answer. I think that computing some Frobenius on a genus 2 curve might not be too hard, but I don't know how many would be needed... | |
Oct 11, 2010 at 9:00 | comment | added | François Brunault | @Kevin Buzzard: I was assuming End(A)=Z because it is the generic case for an abelian surface (and seemingly the most difficult). Also, it was not clear to me when precisely one should expect a Siegel MF (I am not familiar with lifting techniques). But after all, in the classical GL_2 case, weight 2 newforms also give rise to the CM elliptic curves. | |
Oct 5, 2010 at 20:58 | answer | added | Olivier | timeline score: 5 | |
Oct 5, 2010 at 20:09 | comment | added | Kevin Buzzard | @Francois: why would one demand End(A)=Z? If the endomorphisms are bigger then the Galois representation is smaller...aah...OK, I see: are you concerned that in this case the representation might not be cuspidal? | |
Oct 5, 2010 at 20:07 | comment | added | Kevin Buzzard | @Francois: If one can find the candidate Siegel modular form (like Poor/Yuen can do sometimes) then perhaps one can use the strategy I outline in the comments to David Hansen's answer to answer Q1. | |
Oct 5, 2010 at 15:23 | history | edited | Laie |
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Oct 4, 2010 at 15:01 | comment | added | François Brunault | One difficulty in the case $\operatorname{End}_{\overline{\mathbb{Q}}}(A)=\mathbb{Z}$ is that there is apparently no analogue of the Eichler-Schimura construction for Siegel eigenforms (see the introduction of the Brumer/Kramer article). So even for a single explicitly given abelian surface, I wouldn't know how to answer questions 1 and 2 (but maybe I'm wrong). | |
Oct 3, 2010 at 20:52 | comment | added | Laie | This is indeed part of the story. Thanks for catching this glitch, it's corrected now. | |
Oct 3, 2010 at 20:45 | history | edited | Laie | CC BY-SA 2.5 |
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Oct 3, 2010 at 10:46 | comment | added | François Brunault | Shouldn't there be the hypothesis End(A)=Z in the statement of Yoshida's conjecture? | |
Oct 2, 2010 at 0:07 | comment | added | Emerton | ... then modularity of elliptic curves. (One reason that regularity occurs as a hypothesis is that the motives/Galois representations that one can extract from the cohomology of Shimura varieties are regular.) | |
Oct 2, 2010 at 0:06 | comment | added | Emerton | One reason that proving modularity (in the classical, not $p$-adic sense) is harder for abelian surfaces than for elliptic curves is that the Hodge structure of an abelian surface is not regular. We say that a Hodge structure is regular if all $h^{p,q}$ are $\leq 1$. Most modularity theorems have as a hypothesis that the Hodge structure attached to the motive one is trying to show is modular is regular. These don't apply to an abelian surface, since for an abelian surface $h^{1,0} = h^{0,1} = 2$. So, from the point of view of current methods, this is an intrinsically harder question ... | |
Oct 1, 2010 at 20:07 | history | edited | Laie |
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Oct 1, 2010 at 19:31 | comment | added | Laie | For the applications I have in mind p-adic modularity unfortunately doesn't suffice. | |
Oct 1, 2010 at 17:54 | comment | added | Olivier | The answer to question 1 is yes: you want to look at the works of Tilouine, Genestier-Tilouine and most recently V.Pilloni. The article of J.Tilouine which appeared in Compositio Math 142 would seem to be a good starting point for you. Note that typically, these results show p-adic modularity, in the sense that they do not establish that the form is really classical, as you wish. The so-called classicity property is much harder, but might be within reach. | |
Oct 1, 2010 at 15:48 | comment | added | Qiaochu Yuan | +1 for the background! | |
Oct 1, 2010 at 15:29 | answer | added | David Hansen | timeline score: 8 | |
Oct 1, 2010 at 15:00 | history | asked | Laie | CC BY-SA 2.5 |