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Nov 10, 2021 at 11:25 vote accept PAb
S Nov 10, 2021 at 11:24 history bounty ended PAb
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Nov 8, 2021 at 14:09 answer added Narutaka OZAWA timeline score: 8
Nov 8, 2021 at 3:53 answer added Narutaka OZAWA timeline score: 5
Nov 5, 2021 at 12:38 answer added Denis Serre timeline score: 2
Nov 5, 2021 at 11:28 comment added PAb Thanks ! No I did not. However I think the relationship does not hold anymore when subtracting $\lambda Id$ from $M$, so the eigenvalues of $M$ are not those of $N$ and $A$. But maybe we can manage to use this identity to prove the expected result.
Nov 5, 2021 at 10:58 comment added Denis Serre Did you notice the identity $\det M=\det A\det N$ ?
Nov 5, 2021 at 2:13 answer added Michael Renardy timeline score: 2
Nov 4, 2021 at 16:22 history edited PAb CC BY-SA 4.0
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S Nov 4, 2021 at 16:17 history bounty started PAb
S Nov 4, 2021 at 16:17 history notice added PAb Draw attention
Nov 4, 2021 at 1:21 history edited PAb CC BY-SA 4.0
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Nov 3, 2021 at 13:29 comment added PAb Even when n = 1, I am at a loss to prove the result, the closed form expression for the eigenvalues is not informative wolframalpha.com/input/…
Nov 3, 2021 at 13:27 history edited PAb CC BY-SA 4.0
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Nov 2, 2021 at 17:09 history edited PAb CC BY-SA 4.0
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Nov 2, 2021 at 15:57 history asked PAb CC BY-SA 4.0