Timeline for The non empty set of accumulation points of a bounded linear operator is the spectrum of another operator
Current License: CC BY-SA 4.0
8 events
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| Apr 1, 2022 at 9:27 | comment | added | Derek | Maybe I don't understand this question correctly, but any diagonal compact operator K on Hilbert space H has only 0 as an accumulation point, but the only function of K which removes the isolated points is 0, and 0 is an isolated point of the spectrum of the 0 operator, with the eigenspace = H. | |
| Oct 31, 2021 at 17:59 | history | edited | Luffy | CC BY-SA 4.0 |
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| Oct 31, 2021 at 17:58 | comment | added | Luffy | Thanks, but I am looking for how can I remove isolated points from an operator $T$ to find an operator $S_ {T}$ which is a function of $T$ with $\sigma(S_{T})=\mbox{acc}\,\sigma(T)$ and $\mbox{iso}\,\sigma(S_{T})=\emptyset.$ | |
| Oct 31, 2021 at 9:04 | comment | added | hordubal | A subset of the corresponding field, real or complex, is the spectrum of a bounded linear operator if and only if it is compact. | |
| Oct 31, 2021 at 2:55 | review | Close votes | |||
| Nov 2, 2021 at 20:52 | |||||
| Oct 31, 2021 at 2:19 | history | edited | Luffy | CC BY-SA 4.0 |
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| S Oct 31, 2021 at 2:08 | review | First questions | |||
| Oct 31, 2021 at 2:27 | |||||
| S Oct 31, 2021 at 2:08 | history | asked | Luffy | CC BY-SA 4.0 |