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Apr 14, 2023 at 13:20 vote accept Ziad H. Muhammad
Nov 19, 2021 at 13:32 comment added Ziad H. Muhammad Thanks for the answer it seems clearer than how I thought about it. So $\Pi_{tX}(Y_p)\approx Y_{\phi^X(t)}-t\nabla_XY|_{\phi^X(t)}+t^2\nabla^2_XY|_{\phi^X(t)}-...$. Ignoring higher order terms one gets $\Pi_{tX}(Y_p) \approx Y_{\phi^X(t)}-t\nabla_XY|_{\phi^X(t)}$
Oct 27, 2021 at 21:18 review Late answers
Oct 27, 2021 at 22:32
S Oct 27, 2021 at 20:57 review First answers
Oct 27, 2021 at 22:32
S Oct 27, 2021 at 20:57 history answered ESSEFFE CC BY-SA 4.0