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Oct 27, 2021 at 18:52 comment added Fedor Petrov @JosephVanName the result cited by Thomas works for both
Oct 27, 2021 at 18:23 history edited Dominic van der Zypen CC BY-SA 4.0
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Oct 27, 2021 at 18:21 comment added Dominic van der Zypen That's right, Joseph, only distinct prime divisors, so $p(2^5) = 1$. Will edit the original question
Oct 27, 2021 at 13:21 comment added Joseph Van Name Are you counting the number of distinct prime divisors? Is $p(2^{5})=1$? Is $p(2^{5})=5$? en.wikipedia.org/wiki/Prime_omega_function
Oct 27, 2021 at 8:25 comment added Thomas Bloom The median is certainly unbounded, and grows like $\gg \log\log n$. This follows from the fact (Hardy-Ramanujan, reproved by Turan) that $p(a)=(1+o(1))\log\log a$ for almost all integers $a$.
Oct 27, 2021 at 8:15 history edited Dominic van der Zypen CC BY-SA 4.0
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Oct 27, 2021 at 8:08 history asked Dominic van der Zypen CC BY-SA 4.0