Timeline for Does the equation $a^b+b^c+c^a=d^e$ have solutions in $\mathbb {N}$
Current License: CC BY-SA 4.0
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| Oct 25, 2021 at 21:08 | history | edited | Derek Luna | CC BY-SA 4.0 |
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| Oct 24, 2021 at 6:57 | comment | added | Derek Luna | @MattF. It is clear to anyone the poster meant the distinctness requirement, but did not understand the non-transivity of $\neq$. Your suggestion otherwise is completely arbitrary, and I don't think anyone on MSE thought that's what they meant. The motivation is that there are clearly very many solutions (many simple) even when bounding the solutions by a small constant when one allows lack of distinctness, but seemingly none with distinctness. | |
| Oct 24, 2021 at 6:53 | comment | added | user44143 | I downvoted because there is no motivation for the requirement that $a,b,c,d,e$ are all distinct, and because the MathStackExchange question in fact acts about $a\neq b\neq c\neq d\neq e\neq a$ (allowing $a=c$ and the like), which is equally unmotivated but different. | |
| Oct 24, 2021 at 5:26 | history | edited | Derek Luna | CC BY-SA 4.0 |
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| Oct 24, 2021 at 5:25 | history | edited | Daniele Tampieri | CC BY-SA 4.0 |
Minor formatting and grammar improvements.
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| Oct 24, 2021 at 5:14 | history | edited | Derek Luna | CC BY-SA 4.0 |
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| S Oct 24, 2021 at 3:29 | review | First questions | |||
| Oct 24, 2021 at 6:57 | |||||
| S Oct 24, 2021 at 3:29 | history | asked | Derek Luna | CC BY-SA 4.0 |