Timeline for Diophantine equation about the automorphism group of lattice by constraints
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 22, 2021 at 2:04 | comment | added | En-Jui Kuo | n is the number of pauli x, this is correct | |
| Oct 21, 2021 at 22:00 | comment | added | Gerry Myerson | I take it that $n$ is meant to be the number of copies of $\sigma_x$ in the definition of $K_n$. But then I'm confused when you write that you managed to find $W$ for $n=1$, but Mathematica found no solutions. Also, it's not clear to me why this particular $K$ is interesting, nor why the insistence on that particular $2\times2$ lower right corner. | |
| Oct 21, 2021 at 20:19 | history | edited | Michael Hardy | CC BY-SA 4.0 |
added 10 characters in body
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| Oct 21, 2021 at 20:04 | history | edited | En-Jui Kuo | CC BY-SA 4.0 |
deleted 18 characters in body
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| Oct 21, 2021 at 20:03 | comment | added | En-Jui Kuo | OK, I just want to find $n$ and corresponds $W$. I change the text, sorry for the confusion | |
| Oct 21, 2021 at 19:48 | comment | added | Alex M. | Let's use simple English: what do you already know, and what are you looking for? For instance, you say that "My claim is that I should be able to find large enough $n$ such that $K_n=\sigma_x \oplus \sigma_x \oplus \dots \oplus \sigma_x \oplus K$", but a bit further you seem to look for a matrix $W$. I'm confused. | |
| S Oct 21, 2021 at 19:41 | review | First questions | |||
| Oct 21, 2021 at 19:48 | |||||
| S Oct 21, 2021 at 19:41 | history | asked | En-Jui Kuo | CC BY-SA 4.0 |