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Timeline for Consistency proof in topos logic

Current License: CC BY-SA 4.0

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Oct 23, 2021 at 20:39 comment added Paul Blain Levy @PeterLeFanuLumsdaine I've found a reference, Troelstra and van Dalen "Constructivism in Mathematics, an introduction", Volume 1, Chapter 3, Section 9.3. I should have searched before asking you!
Oct 23, 2021 at 20:14 comment added Peter LeFanu Lumsdaine @PaulBlainLevy: off the top of my head, I’m not sure of a reference that gives it syntactically — my first hope was Lambek & Scott, but I can’t find it there. Mac Lane and Moerdijk Theorem VI.1.3 shows that “in any topos, the subtopos of $\lnot \lnot$-sheaves is Boolean”, which directly implies the syntactic translation.
Oct 23, 2021 at 19:44 comment added Paul Blain Levy @PeterLeFanuLumsdaine is there a reference for that double-negation translation? So that I can refer to it without having to write it out.
Oct 23, 2021 at 19:36 comment added Paul Blain Levy Thanks! I have accordingly removed the supplement to my question. It claimed that Bounded Zermelo is conservative over PA$_{\omega}$, and I'm not entirely sure of this, though it does seem plausible.
Oct 22, 2021 at 7:15 history edited Andrej Bauer CC BY-SA 4.0
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Oct 22, 2021 at 7:11 comment added Andrej Bauer @PaulBlainLevy: \nat is self-explanatory, I wouldn't worry about it. But to explain what your comment is about, I added an explanation.
Oct 22, 2021 at 0:50 vote accept Paul Blain Levy
Oct 22, 2021 at 0:49 comment added Paul Blain Levy \nats should be $\mathbb{N}$ in my comment.
Oct 19, 2021 at 6:37 comment added Peter LeFanu Lumsdaine Another way to see this answer is: $HOL_N$ (classical higher-order logic with NNO; the logic of a Boolean topos with NMO) clearly proves the consistency of each $PA_n$. But $HOL_N$ translates into $IHOL_N$ via the double-negation translation.
Oct 19, 2021 at 6:23 comment added Paul Blain Levy Great answer, Andrej, but I think you slightly overstated. What this shows is that, for each $n \in \nats$, topos-with-nno logic can build a model of PA$_{n+1}$. I've edited my question to make this clearer.
Oct 19, 2021 at 5:40 comment added Paul Blain Levy [Deleted earlier comment - I hadn't read your message carefully.]
Oct 17, 2021 at 20:08 history answered Andrej Bauer CC BY-SA 4.0