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Oct 20, 2021 at 14:00 vote accept Felipe Augusto de Figueiredo
Oct 18, 2021 at 0:41 answer added Felipe Augusto de Figueiredo timeline score: 3
Oct 17, 2021 at 19:28 comment added username If you are asking whether this integral is well defined, for any $a>0$ and $d>0$, the answer is that the integrand is equivalent near the origin to $x^{-\alpha}\exp( -\frac{c^2}{2}x^{-2d})$ so : - if $c=0$, it is finite only when $a<1$ - if $c\neq0$ it tends to zero very fast, and it therefore extendable by continuity. If you are asking for an explicit formula, math stack exchange is a better choice.
Oct 17, 2021 at 18:50 answer added Carlo Beenakker timeline score: 4
Oct 17, 2021 at 18:48 answer added Gerald Edgar timeline score: 5
Oct 17, 2021 at 18:47 comment added Felipe Augusto de Figueiredo @CarloBeenakker the indefinite integral might also help. Thanks!
Oct 17, 2021 at 18:45 comment added Carlo Beenakker you want the indefinite integral, if has a closed form expression for $b=0$, but not in general I think.
Oct 17, 2021 at 17:21 comment added Sidharth Ghoshal This will probably attract more attention at math.stackexchange.com than here. I believe there are more integral-buffs hanging out there (Even for very hard integrals) than mathoverflow
Oct 17, 2021 at 14:52 history edited Felipe Augusto de Figueiredo CC BY-SA 4.0
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Oct 17, 2021 at 14:41 history asked Felipe Augusto de Figueiredo CC BY-SA 4.0