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Oct 14, 2021 at 18:21 vote accept Ian Gershon Teixeira
Oct 14, 2021 at 13:12 answer added David E Speyer timeline score: 2
Oct 14, 2021 at 12:50 history edited YCor CC BY-SA 4.0
formatting, added tag
Oct 14, 2021 at 12:33 comment added Ian Gershon Teixeira I just meant maximal closed. In my head I say "almost dense" instead of maximal closed because I think it's more interesting to frame it as "this subgroup is so close to being dense that if you add any single new element and take the closure of the group generated that way you get every element of $G_\mathbb{R}$". So I use "maximal closed subgroup" and "almost dense subgroup" interchangeably and that was supposed to say almost dense
Oct 14, 2021 at 12:29 history edited Ian Gershon Teixeira CC BY-SA 4.0
deleted 23 characters in body
Oct 14, 2021 at 9:05 history became hot network question
Oct 14, 2021 at 3:24 answer added Venkataramana timeline score: 8
Oct 14, 2021 at 2:59 history edited LSpice CC BY-SA 4.0
Proofreading; `\operatorname`
Oct 14, 2021 at 2:57 comment added LSpice By "Integer points are in dense for $\operatorname{SO}_3$", do you mean "the integer points form a maximal closed subgroup of the real points when $G = \operatorname{SO}_3$" or something? \\ Also, the hypothesis 'simple' should probably go in the title; otherwise the additive group $G$ is a counterexample.
Oct 14, 2021 at 2:29 comment added Ian Gershon Teixeira haha oops I just fixed it with an edit
Oct 14, 2021 at 2:29 history edited Ian Gershon Teixeira CC BY-SA 4.0
added 21 characters in body
Oct 14, 2021 at 1:22 comment added Francois Ziegler Where by “no” you mean “yes”?
Oct 14, 2021 at 1:05 history asked Ian Gershon Teixeira CC BY-SA 4.0