Timeline for Proof: If a reproducing kernel exists for a Hilbert space, then it is unique
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 10, 2021 at 18:27 | comment | added | Pinch | Got it, thank you all so much! | |
| Oct 10, 2021 at 18:19 | comment | added | Mark Wildon | Apply (1) replacing $k_x$ with $\hat{k}_x$ (legitimate since $\hat{k}$ and $k$ have the same properties) and $f$ with $k_x$. | |
| Oct 10, 2021 at 18:18 | comment | added | Pinch | First of all, thanks for the quick answer! But sadly I still do not understand, why I can rewrite $\langle k_x, \hat{k}_x \rangle$ as $k_x(x)$ (and $\langle \hat{k}_x, k_x \rangle$ as $\hat{k}_x(x)$)... | |
| Oct 10, 2021 at 18:11 | vote | accept | Pinch | ||
| Oct 10, 2021 at 17:49 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 42 characters in body
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| Oct 10, 2021 at 17:43 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |