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Oct 11, 2021 at 14:47 comment added dohmatob Ah, yes that makes sense on second thought. Thanks. Any idea what the coefficient of $t^k$ (for $k \ge 2$; especially the case $k=2$) would be ? I'm suspecting it would be something like $\mathcal O(1/d^k)$. To get this kind of information, one would have to use a higher-order expansion of the Hermite polynomial expressions (in the integral) around $r=0$, right ?
Oct 11, 2021 at 14:42 comment added Carlo Beenakker no, I would think that the error term is of order $1/d^2$.
Oct 11, 2021 at 14:31 comment added dohmatob Do we have a rough idea how small the error term ignored in the above approximation of $s_{nm}$ is ? For example, is it by any chance of order $\mathcal O(1/d^{2 + \varepsilon})$ for some $\varepsilon>0$ ?
Oct 10, 2021 at 18:19 history edited Carlo Beenakker CC BY-SA 4.0
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Oct 10, 2021 at 18:16 vote accept dohmatob
Oct 10, 2021 at 18:16 comment added dohmatob This is quite instructive. Thanks!
Oct 10, 2021 at 18:13 vote accept dohmatob
Oct 10, 2021 at 18:13
Oct 10, 2021 at 17:55 history edited Carlo Beenakker CC BY-SA 4.0
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Oct 10, 2021 at 17:48 history edited Carlo Beenakker CC BY-SA 4.0
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Oct 10, 2021 at 17:26 history answered Carlo Beenakker CC BY-SA 4.0