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Oct 10, 2021 at 11:29 comment added Mikhail Borovoi It is a calculation. Your homogeneous space $X$ has dimension $12-4=8$. You should try to construct a Borel subgroup $B$ such that $B\cap H$ has dimension one. Since $B$ is of dimension $9$, you will see that the $B$-orbit $B\cdot 1H\subset G/H$ is of dimension 8, hence dense (and open).
Oct 10, 2021 at 8:47 history edited Mikhail Borovoi
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Oct 10, 2021 at 6:51 comment added user130903 Using the obvious Isomorphism to $GL_2\times GL_2$, you can rule that out by dimension count.
Oct 10, 2021 at 6:32 history asked user42804 CC BY-SA 4.0