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Oct 10, 2021 at 6:27 vote accept GJC20
Oct 10, 2021 at 4:06 answer added Iosif Pinelis timeline score: 1
Oct 9, 2021 at 16:50 comment added Yuval Peres I deleted my comment.
Oct 9, 2021 at 16:49 comment added GJC20 @YuvalPeres I think $\lim_{t\to\infty}X^k_t=\infty$ with $X^k_t:=2+\beta t+W_t-k(t)$, while $\mathbb P[\tau_k=\infty]=\mathbb P[X^k_t>0, \forall t\ge 0]>1$
Oct 9, 2021 at 16:44 comment added GJC20 @ChristianRemling Thanks for the hint. I think I know how to prove the strict inequality
Oct 8, 2021 at 17:12 comment added Christian Remling You also have $k(t)\le a<b\le h(t)$ on a suitable time interval, and the probability of hitting $(a,b)$ during that interval is non-zero.
Oct 8, 2021 at 16:32 history asked GJC20 CC BY-SA 4.0